gc: fix chan <- chan precedence.

also allow func() func().

R=ken2
CC=golang-dev
https://golang.org/cl/194078

1 files changed, 0 insertions, 39 deletions

diff --git a/test/bugs/bug249.go b/test/bugs/bug249.go
deleted file mode 100644
index 642170d072..0000000000
--- a/test/bugs/bug249.go
+++ /dev/null
@@ -1,39 +0,0 @@
-// errchk $G $D/$F.go
-
-// Copyright 2009 The Go Authors.  All rights reserved.
-// Use of this source code is governed by a BSD-style
-// license that can be found in the LICENSE file.
-
-package main
-
-var c1 chan<- chan int
-var c2 chan<- (chan int) // same type as c1 according to gccgo, gofmt
-var c3 chan (<-chan int) // same type as c1 according to 6g
-
-func main() {
-	c1 = c2 // this should be ok, bug 6g doesn't accept it
-	c1 = c3 // ERROR "chan"
-}
-
-/*
-Channel types are parsed differently by 6g then by gccgo and gofmt.
-The channel type specification ( http://golang.org/doc/go_spec.html#Channel_types )
-says that a channel type is either
-
-	chan ElementType
-	chan <- ElementType
-	<-chan ElementType
-
-which indicates that the <- binds to the chan token (not to the ElementType).
-So:
-
-chan <- chan int
-
-should be parsed as
-
-chan<- (chan int)
-
-Both gccgo and gofmt adhere to this, while 6g parses this as
-
-chan (<-chan int)
-*/