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authorKatie Hockman <katie@golang.org>2020-12-14 10:03:05 -0500
committerKatie Hockman <katie@golang.org>2020-12-14 10:06:13 -0500
commit0345ede87ee12698988973884cfc0fd3d499dffd (patch)
tree7123cff141ee5661208d2f5f437b8f5252ac7f6a /src/math/big/arith.go
parent4651d6b267818b0e0d128a5443289717c4bb8cbc (diff)
parent0a02371b0576964e81c3b40d328db9a3ef3b031b (diff)
downloadgo-0345ede87ee12698988973884cfc0fd3d499dffd.tar.xz
[dev.fuzz] all: merge master into dev.fuzz
Change-Id: I5d8c8329ccc9d747bd81ade6b1cb7cb8ae2e94b2
Diffstat (limited to 'src/math/big/arith.go')
-rw-r--r--src/math/big/arith.go89
1 files changed, 80 insertions, 9 deletions
diff --git a/src/math/big/arith.go b/src/math/big/arith.go
index b0885f261f..750ce8aa39 100644
--- a/src/math/big/arith.go
+++ b/src/math/big/arith.go
@@ -60,12 +60,6 @@ func nlz(x Word) uint {
return uint(bits.LeadingZeros(uint(x)))
}
-// q = (u1<<_W + u0 - r)/v
-func divWW_g(u1, u0, v Word) (q, r Word) {
- qq, rr := bits.Div(uint(u1), uint(u0), uint(v))
- return Word(qq), Word(rr)
-}
-
// The resulting carry c is either 0 or 1.
func addVV_g(z, x, y []Word) (c Word) {
// The comment near the top of this file discusses this for loop condition.
@@ -207,10 +201,87 @@ func addMulVVW_g(z, x []Word, y Word) (c Word) {
return
}
-func divWVW_g(z []Word, xn Word, x []Word, y Word) (r Word) {
+// q = ( x1 << _W + x0 - r)/y. m = floor(( _B^2 - 1 ) / d - _B). Requiring x1<y.
+// An approximate reciprocal with a reference to "Improved Division by Invariant Integers
+// (IEEE Transactions on Computers, 11 Jun. 2010)"
+func divWW(x1, x0, y, m Word) (q, r Word) {
+ s := nlz(y)
+ if s != 0 {
+ x1 = x1<<s | x0>>(_W-s)
+ x0 <<= s
+ y <<= s
+ }
+ d := uint(y)
+ // We know that
+ // m = ⎣(B^2-1)/d⎦-B
+ // ⎣(B^2-1)/d⎦ = m+B
+ // (B^2-1)/d = m+B+delta1 0 <= delta1 <= (d-1)/d
+ // B^2/d = m+B+delta2 0 <= delta2 <= 1
+ // The quotient we're trying to compute is
+ // quotient = ⎣(x1*B+x0)/d⎦
+ // = ⎣(x1*B*(B^2/d)+x0*(B^2/d))/B^2⎦
+ // = ⎣(x1*B*(m+B+delta2)+x0*(m+B+delta2))/B^2⎦
+ // = ⎣(x1*m+x1*B+x0)/B + x0*m/B^2 + delta2*(x1*B+x0)/B^2⎦
+ // The latter two terms of this three-term sum are between 0 and 1.
+ // So we can compute just the first term, and we will be low by at most 2.
+ t1, t0 := bits.Mul(uint(m), uint(x1))
+ _, c := bits.Add(t0, uint(x0), 0)
+ t1, _ = bits.Add(t1, uint(x1), c)
+ // The quotient is either t1, t1+1, or t1+2.
+ // We'll try t1 and adjust if needed.
+ qq := t1
+ // compute remainder r=x-d*q.
+ dq1, dq0 := bits.Mul(d, qq)
+ r0, b := bits.Sub(uint(x0), dq0, 0)
+ r1, _ := bits.Sub(uint(x1), dq1, b)
+ // The remainder we just computed is bounded above by B+d:
+ // r = x1*B + x0 - d*q.
+ // = x1*B + x0 - d*⎣(x1*m+x1*B+x0)/B⎦
+ // = x1*B + x0 - d*((x1*m+x1*B+x0)/B-alpha) 0 <= alpha < 1
+ // = x1*B + x0 - x1*d/B*m - x1*d - x0*d/B + d*alpha
+ // = x1*B + x0 - x1*d/B*⎣(B^2-1)/d-B⎦ - x1*d - x0*d/B + d*alpha
+ // = x1*B + x0 - x1*d/B*⎣(B^2-1)/d-B⎦ - x1*d - x0*d/B + d*alpha
+ // = x1*B + x0 - x1*d/B*((B^2-1)/d-B-beta) - x1*d - x0*d/B + d*alpha 0 <= beta < 1
+ // = x1*B + x0 - x1*B + x1/B + x1*d + x1*d/B*beta - x1*d - x0*d/B + d*alpha
+ // = x0 + x1/B + x1*d/B*beta - x0*d/B + d*alpha
+ // = x0*(1-d/B) + x1*(1+d*beta)/B + d*alpha
+ // < B*(1-d/B) + d*B/B + d because x0<B (and 1-d/B>0), x1<d, 1+d*beta<=B, alpha<1
+ // = B - d + d + d
+ // = B+d
+ // So r1 can only be 0 or 1. If r1 is 1, then we know q was too small.
+ // Add 1 to q and subtract d from r. That guarantees that r is <B, so
+ // we no longer need to keep track of r1.
+ if r1 != 0 {
+ qq++
+ r0 -= d
+ }
+ // If the remainder is still too large, increment q one more time.
+ if r0 >= d {
+ qq++
+ r0 -= d
+ }
+ return Word(qq), Word(r0 >> s)
+}
+
+func divWVW(z []Word, xn Word, x []Word, y Word) (r Word) {
r = xn
+ if len(x) == 1 {
+ qq, rr := bits.Div(uint(r), uint(x[0]), uint(y))
+ z[0] = Word(qq)
+ return Word(rr)
+ }
+ rec := reciprocalWord(y)
for i := len(z) - 1; i >= 0; i-- {
- z[i], r = divWW_g(r, x[i], y)
+ z[i], r = divWW(r, x[i], y, rec)
}
- return
+ return r
+}
+
+// reciprocalWord return the reciprocal of the divisor. rec = floor(( _B^2 - 1 ) / u - _B). u = d1 << nlz(d1).
+func reciprocalWord(d1 Word) Word {
+ u := uint(d1 << nlz(d1))
+ x1 := ^u
+ x0 := uint(_M)
+ rec, _ := bits.Div(x1, x0, u) // (_B^2-1)/U-_B = (_B*(_M-C)+_M)/U
+ return Word(rec)
}