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| author | Katie Hockman <katie@golang.org> | 2020-12-14 10:03:05 -0500 |
|---|---|---|
| committer | Katie Hockman <katie@golang.org> | 2020-12-14 10:06:13 -0500 |
| commit | 0345ede87ee12698988973884cfc0fd3d499dffd (patch) | |
| tree | 7123cff141ee5661208d2f5f437b8f5252ac7f6a /src/math/big/arith.go | |
| parent | 4651d6b267818b0e0d128a5443289717c4bb8cbc (diff) | |
| parent | 0a02371b0576964e81c3b40d328db9a3ef3b031b (diff) | |
| download | go-0345ede87ee12698988973884cfc0fd3d499dffd.tar.xz | |
[dev.fuzz] all: merge master into dev.fuzz
Change-Id: I5d8c8329ccc9d747bd81ade6b1cb7cb8ae2e94b2
Diffstat (limited to 'src/math/big/arith.go')
| -rw-r--r-- | src/math/big/arith.go | 89 |
1 files changed, 80 insertions, 9 deletions
diff --git a/src/math/big/arith.go b/src/math/big/arith.go index b0885f261f..750ce8aa39 100644 --- a/src/math/big/arith.go +++ b/src/math/big/arith.go @@ -60,12 +60,6 @@ func nlz(x Word) uint { return uint(bits.LeadingZeros(uint(x))) } -// q = (u1<<_W + u0 - r)/v -func divWW_g(u1, u0, v Word) (q, r Word) { - qq, rr := bits.Div(uint(u1), uint(u0), uint(v)) - return Word(qq), Word(rr) -} - // The resulting carry c is either 0 or 1. func addVV_g(z, x, y []Word) (c Word) { // The comment near the top of this file discusses this for loop condition. @@ -207,10 +201,87 @@ func addMulVVW_g(z, x []Word, y Word) (c Word) { return } -func divWVW_g(z []Word, xn Word, x []Word, y Word) (r Word) { +// q = ( x1 << _W + x0 - r)/y. m = floor(( _B^2 - 1 ) / d - _B). Requiring x1<y. +// An approximate reciprocal with a reference to "Improved Division by Invariant Integers +// (IEEE Transactions on Computers, 11 Jun. 2010)" +func divWW(x1, x0, y, m Word) (q, r Word) { + s := nlz(y) + if s != 0 { + x1 = x1<<s | x0>>(_W-s) + x0 <<= s + y <<= s + } + d := uint(y) + // We know that + // m = ⎣(B^2-1)/d⎦-B + // ⎣(B^2-1)/d⎦ = m+B + // (B^2-1)/d = m+B+delta1 0 <= delta1 <= (d-1)/d + // B^2/d = m+B+delta2 0 <= delta2 <= 1 + // The quotient we're trying to compute is + // quotient = ⎣(x1*B+x0)/d⎦ + // = ⎣(x1*B*(B^2/d)+x0*(B^2/d))/B^2⎦ + // = ⎣(x1*B*(m+B+delta2)+x0*(m+B+delta2))/B^2⎦ + // = ⎣(x1*m+x1*B+x0)/B + x0*m/B^2 + delta2*(x1*B+x0)/B^2⎦ + // The latter two terms of this three-term sum are between 0 and 1. + // So we can compute just the first term, and we will be low by at most 2. + t1, t0 := bits.Mul(uint(m), uint(x1)) + _, c := bits.Add(t0, uint(x0), 0) + t1, _ = bits.Add(t1, uint(x1), c) + // The quotient is either t1, t1+1, or t1+2. + // We'll try t1 and adjust if needed. + qq := t1 + // compute remainder r=x-d*q. + dq1, dq0 := bits.Mul(d, qq) + r0, b := bits.Sub(uint(x0), dq0, 0) + r1, _ := bits.Sub(uint(x1), dq1, b) + // The remainder we just computed is bounded above by B+d: + // r = x1*B + x0 - d*q. + // = x1*B + x0 - d*⎣(x1*m+x1*B+x0)/B⎦ + // = x1*B + x0 - d*((x1*m+x1*B+x0)/B-alpha) 0 <= alpha < 1 + // = x1*B + x0 - x1*d/B*m - x1*d - x0*d/B + d*alpha + // = x1*B + x0 - x1*d/B*⎣(B^2-1)/d-B⎦ - x1*d - x0*d/B + d*alpha + // = x1*B + x0 - x1*d/B*⎣(B^2-1)/d-B⎦ - x1*d - x0*d/B + d*alpha + // = x1*B + x0 - x1*d/B*((B^2-1)/d-B-beta) - x1*d - x0*d/B + d*alpha 0 <= beta < 1 + // = x1*B + x0 - x1*B + x1/B + x1*d + x1*d/B*beta - x1*d - x0*d/B + d*alpha + // = x0 + x1/B + x1*d/B*beta - x0*d/B + d*alpha + // = x0*(1-d/B) + x1*(1+d*beta)/B + d*alpha + // < B*(1-d/B) + d*B/B + d because x0<B (and 1-d/B>0), x1<d, 1+d*beta<=B, alpha<1 + // = B - d + d + d + // = B+d + // So r1 can only be 0 or 1. If r1 is 1, then we know q was too small. + // Add 1 to q and subtract d from r. That guarantees that r is <B, so + // we no longer need to keep track of r1. + if r1 != 0 { + qq++ + r0 -= d + } + // If the remainder is still too large, increment q one more time. + if r0 >= d { + qq++ + r0 -= d + } + return Word(qq), Word(r0 >> s) +} + +func divWVW(z []Word, xn Word, x []Word, y Word) (r Word) { r = xn + if len(x) == 1 { + qq, rr := bits.Div(uint(r), uint(x[0]), uint(y)) + z[0] = Word(qq) + return Word(rr) + } + rec := reciprocalWord(y) for i := len(z) - 1; i >= 0; i-- { - z[i], r = divWW_g(r, x[i], y) + z[i], r = divWW(r, x[i], y, rec) } - return + return r +} + +// reciprocalWord return the reciprocal of the divisor. rec = floor(( _B^2 - 1 ) / u - _B). u = d1 << nlz(d1). +func reciprocalWord(d1 Word) Word { + u := uint(d1 << nlz(d1)) + x1 := ^u + x0 := uint(_M) + rec, _ := bits.Div(x1, x0, u) // (_B^2-1)/U-_B = (_B*(_M-C)+_M)/U + return Word(rec) } |
