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authorDaniel Martí <mvdan@mvdan.cc>2023-01-12 18:29:28 +0000
committerDaniel Martí <mvdan@mvdan.cc>2023-04-11 06:26:36 +0000
commite21d126ee13031e0fb621e4ec66ae1be403e2d36 (patch)
tree02bacedc8e37b59da4c3cf209c717f4c6ac24632 /src/debug
parent96428e160de755d6b3b3b7dc1b9c81196957d679 (diff)
downloadgo-e21d126ee13031e0fb621e4ec66ae1be403e2d36.tar.xz
go/printer: reuse go/token.FileSet.PositionFor calls in setPos
setPos is called for most nodes, and in a number of cases, the position is already the same. PositionFor is a relatively expensive call, as it needs to "unpack" a token.Pos into a token.Position. If we can tell that the position is the same in a cheap way, we can then avoid calling setPos and PositionFor. Luckily, we can get the position's offset within the file, and it doesn't involve the relatively expensive unpacking. name old time/op new time/op delta PrintFile-16 4.79ms ± 1% 4.36ms ± 1% -8.88% (p=0.008 n=5+5) name old speed new speed delta PrintFile-16 10.8MB/s ± 1% 11.9MB/s ± 1% +9.73% (p=0.008 n=5+5) name old alloc/op new alloc/op delta PrintFile-16 106kB ± 1% 106kB ± 1% ~ (p=0.167 n=5+5) name old allocs/op new allocs/op delta PrintFile-16 2.42k ± 0% 2.42k ± 0% ~ (all equal) This does assume that the positions of a node being printed are all within a file, as go/token.Position.Offset is relative to each file. This seems like a perfectly fine assumption to make right now, as the largest node which can be printed is an *ast.File. Change-Id: I2ae55f507ba8ba9f280898c9c8e01c994d9b2a26 Reviewed-on: https://go-review.googlesource.com/c/go/+/461739 Reviewed-by: Robert Griesemer <gri@google.com> Run-TryBot: Robert Griesemer <gri@google.com> TryBot-Result: Gopher Robot <gobot@golang.org> Reviewed-by: David Chase <drchase@google.com>
Diffstat (limited to 'src/debug')
0 files changed, 0 insertions, 0 deletions