lib/play: expose the Timeout variable

By exposing the Timeout, user can set their maximum time the program
can run in their playground.

2 files changed, 5 insertions, 3 deletions

diff --git a/lib/play/command.go b/lib/play/command.go
index 2cbed88e..f3812dbe 100644
--- a/lib/play/command.go
+++ b/lib/play/command.go
@@ -23,14 +23,12 @@ type command struct {
 }
 
 func newCommand(req *Request, workingDir string) (cmd *command, err error) {
-	const defCommandTimeout = 30 * time.Second
-
 	cmd = &command{
 		buf: &bytes.Buffer{},
 		pid: make(chan int, 1),
 	}
 	var ctxParent = context.Background()
-	cmd.ctx, cmd.ctxCancel = context.WithTimeout(ctxParent, defCommandTimeout)
+	cmd.ctx, cmd.ctxCancel = context.WithTimeout(ctxParent, Timeout)
 
 	var userHomeDir string
 
diff --git a/lib/play/play.go b/lib/play/play.go
index 6ea179c5..6abd79a8 100644
--- a/lib/play/play.go
+++ b/lib/play/play.go
@@ -50,6 +50,10 @@ import (
 // code.
 var GoVersion = `1.23.2`
 
+// Timeout define the maximum time the program can be run until it get
+// terminated.
+var Timeout = 10 * time.Second
+
 var gomodTemplate = `
 module play.local